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Consider $4 x^{2} + 4 (m - 1) x + 1 = 0$ . For the roots to be real and equal, find the smaller value of $m$ .

Class 10Discriminant and Nature of RootsAlgebra — Quadratics

A0
B2
C1
D-1

Step-by-Step Solution

D = 0 : [4 (m - 1)]^{2} - 4 (4) (1) = 0

, so

16 (m - 1)^{2} = 16, (m - 1)^{2} = 1, m - 1 = + / - 1

, giving

m = 2

or

m = 0

. The smaller value is 0.

Answer: A) 0

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