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The discriminant of $p x^{2} + q x + r = 0 (p$ not equal to 0) is $q^{2} - 4 p r$ . For $p x^{2} - q x + r = 0$ , the discriminant is:

Class 10Discriminant and Nature of RootsAlgebra — Quadratics

A $q^{2} - 4 p r$
B $q^{2} + 4 p r$
C $- q^{2} - 4 p r$
D $4 p r - q^{2}$

Step-by-Step Solution

With coefficient -q, the discriminant is

(- q)^{2} - 4 p r = q^{2} - 4 p r

, the same value.

Answer: A)

q^{2} - 4 p r

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