The product of two consecutive positive integers is 56. Modelling the smaller as x gives x^2 + x - 56 = 0. Without solving fully, what is the discriminant, and hence the nature of roots?

Question

Accepted Answer

225; real and distinct. a = 1, b = 1, c = -56. D = 1 + 224 = 225 > 0 (and a perfect square), so roots are real and distinct (x = 7 and x = -8).

The product of two consecutive positive integers is 56. Modelling the smaller as $x$ gives $x^{2} + x - 56 = 0$ .
Without solving fully, what is the discriminant, and hence the nature of roots?

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More Class 10 Discriminant and Nature of Roots practice

The product of two consecutive positive integers is 56. Modelling the smaller as x gives x2+x−56=0.Without solving fully, what is the discriminant, and hence the nature of roots?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Discriminant and Nature of Roots practice

The product of two consecutive positive integers is 56. Modelling the smaller as $x$ gives $x^{2} + x - 56 = 0$ .
Without solving fully, what is the discriminant, and hence the nature of roots?