A circular park has its centre at O(4, 6) and one of its gates at G(-4, 0), the units being metres. A jogger enters at the gate and runs in a straight line through the centre to the boundary point directly opposite. How far does she run?

Question

Accepted Answer

20 m. The gate is on the boundary, so OG = √(-4-4)^2 + (0-6)^2 = √64+36 = 10 m is the radius. Running from the gate through the centre to the far boundary covers a full diameter, 2 × 10 = 20 m. Stopping at 10 m answers with the radius only, and 14 m comes from adding 8 + 6 instead of using the distance formula.

A circular park has its centre at O(4, 6) and one of its gates at G(-4, 0), the units being metres. A jogger enters at the gate and runs in a straight line through the centre to the boundary point directly opposite.
How far does she run?

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More Class 10 Distance Formula practice

A circular park has its centre at O(4, 6) and one of its gates at G(-4, 0), the units being metres. A jogger enters at the gate and runs in a straight line through the centre to the boundary point directly opposite.How far does she run?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Distance Formula practice

A circular park has its centre at O(4, 6) and one of its gates at G(-4, 0), the units being metres. A jogger enters at the gate and runs in a straight line through the centre to the boundary point directly opposite.
How far does she run?