A flower bed has corners at A(-1, 1), B(2, 5), C(7, 5) and D(4, 1), the units being metres. Metal edging is to be fixed all the way round the bed.
What length of edging is needed?

Question

A flower bed has corners at A(-1, 1), B(2, 5), C(7, 5) and D(4, 1), the units being metres. Metal edging is to be fixed all the way round the bed. What length of edging is needed?

Accepted Answer

20 m. AB = √(2+1)^2 + (5-1)^2 = √9+16 = 5, BC = |7 - 2| = 5, CD = √(4-7)^2 + (1-5)^2 = 5 and DA = |4 - (-1)| = 5. All four sides measure 5 m, so the edging needed is 4 × 5 = 20 m. The bed is a rhombus, not a square: its diagonals are AC = √64+16 = 4√5 and BD = √4+16 = 2√5, which are unequal. 25 m comes from squaring the side instead of adding the four sides.

A flower bed has corners at A(-1, 1), B(2, 5), C(7, 5) and D(4, 1), the units being metres. Metal edging is to be fixed all the way round the bed.
What length of edging is needed?

Step-by-Step Solution

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More Class 10 Distance Formula practice

A flower bed has corners at A(-1, 1), B(2, 5), C(7, 5) and D(4, 1), the units being metres. Metal edging is to be fixed all the way round the bed.What length of edging is needed?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Distance Formula practice

A flower bed has corners at A(-1, 1), B(2, 5), C(7, 5) and D(4, 1), the units being metres. Metal edging is to be fixed all the way round the bed.
What length of edging is needed?