If the point (x, y) is equidistant from A(7, 1) and B(3, 5), the relation between x and y is:

Question

Accepted Answer

y = x - 2. Equate squared distances: (x-7)^2 + (y-1)^2 = (x-3)^2 + (y-5)^2. Expand: -14x+49-2y+1 = -6x+9-10y+25, so -14x-2y+50 = -6x-10y+34, giving 8y = 8x - 16, y = x - 2.

If the point $(x, y)$ is equidistant from A(7, 1) and B(3, 5), the relation between $x$ and $y$ is:

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More Class 10 Distance Formula practice

If the point (x,y) is equidistant from A(7, 1) and B(3, 5), the relation between x and y is:

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Distance Formula practice

If the point $(x, y)$ is equidistant from A(7, 1) and B(3, 5), the relation between $x$ and $y$ is: