Prove using Euclid's Division Lemma that the product of three consecutive positive integers is divisible by 6. The smallest such product (for 1 x 2 x 3) is 6, confirming divisibility. What is the product 4 x 5 x 6 divided by 6?

Question

Accepted Answer

20. Among any 3 consecutive integers one is divisible by 2 and one by 3, so product is divisible by 6. 4 x 5 x 6 = 120; 120 / 6 = 20.

Prove using Euclid's Division Lemma that the product of three consecutive positive integers is divisible by 6.
The smallest such product (for $1 \times 2 \times$ 3) is 6, confirming divisibility. What is the product $4 \times 5 \times$ 6 divided by 6?

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More Class 10 Euclid's Division Lemma practice

Prove using Euclid's Division Lemma that the product of three consecutive positive integers is divisible by 6.The smallest such product (for 1×2× 3) is 6, confirming divisibility. What is the product 4×5× 6 divided by 6?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Euclid's Division Lemma practice

Prove using Euclid's Division Lemma that the product of three consecutive positive integers is divisible by 6.
The smallest such product (for $1 \times 2 \times$ 3) is 6, confirming divisibility. What is the product $4 \times 5 \times$ 6 divided by 6?