A frustum-shaped water cooler has end radii 25 cm and 15 cm and a depth of 9 cm. How many litres does it hold? (Take \π = 22/7 , 1 litre = 1000 cm³.)

Question

Accepted Answer

11.55 litres. V = 1/3 × 22/7 × 9 × (625 + 225 + 375) = 22/7 × 3 × 1225 = 22 × 3 × 175 = 11550 cm³ = 11.55 litres. 115.5 and 1.155 come from dividing by 100 or by 10000 instead of 1000; 8.01 litres comes from dropping the Rr term (using 850 instead of 1225).

A frustum-shaped water cooler has end radii 25 cm and 15 cm and a depth of 9 cm. How many litres does it hold? (Take $π = \frac{22}{7}$ , 1 litre = $1000 cm^{3} .$ )

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More Class 10 Frustum of a Cone practice

A frustum-shaped water cooler has end radii 25 cm and 15 cm and a depth of 9 cm. How many litres does it hold? (Take π=722​, 1 litre = 1000cm3.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

A frustum-shaped water cooler has end radii 25 cm and 15 cm and a depth of 9 cm. How many litres does it hold? (Take $π = \frac{22}{7}$ , 1 litre = $1000 cm^{3} .$ )