A solid brass paperweight is a frustum with end radii 13 cm and 5 cm and a vertical height of 6 cm. Its whole outer surface, including both flat circular faces, is to be polished. Find that area, in cm². (Take \π = 3.14 .)

Question

Accepted Answer

1174.36. l = √6^2 + 8^2 = 10 cm. TSA = \π l (R + r) + \π R^2 + \π r^2 = 3.14(10 × 18) + 3.14 × 169 + 3.14 × 25 = 565.2 + 530.66 + 78.5 = 1174.36 cm². 565.2 is the curved surface alone; 1095.86 leaves out the small end; 948.28 uses the height 6 cm in place of the slant height 10 cm.

A solid brass paperweight is a frustum with end radii 13 cm and 5 cm and a vertical height of 6 cm. Its whole outer surface, including both flat circular faces, is to be polished. Find that area, in $cm^{2}$ . (Take $π = 3.14.$ )

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More Class 10 Frustum of a Cone practice

A solid brass paperweight is a frustum with end radii 13 cm and 5 cm and a vertical height of 6 cm. Its whole outer surface, including both flat circular faces, is to be polished. Find that area, in cm2. (Take π=3.14.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

A solid brass paperweight is a frustum with end radii 13 cm and 5 cm and a vertical height of 6 cm. Its whole outer surface, including both flat circular faces, is to be polished. Find that area, in $cm^{2}$ . (Take $π = 3.14.$ )