An open frustum-shaped bucket has radii 28 cm and 21 cm and slant height 30 cm. Find the area of metal sheet required to make it (curved surface + bottom circle only), in cm^2 (use π = 22/7).

Question

Accepted Answer

6006. Curved = 22/7*30*(28 + 21) = 22/7*30*49 = 22*30*7 = 4620. Bottom (r = 21) = 22/7*21^2 = 22/7*441 = 22*63 = 1386. Total = 4620 + 1386 = 6006 cm^2.

An open frustum-shaped bucket has radii 28 cm and 21 cm and slant height 30 cm.
Find the area of metal sheet required to make it (curved surface + bottom circle only), in $cm^{2}$ (use π = $\frac{22}{7}$ ).

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More Class 10 Frustum of a Cone practice

An open frustum-shaped bucket has radii 28 cm and 21 cm and slant height 30 cm.Find the area of metal sheet required to make it (curved surface + bottom circle only), in cm2 (use π = 722​).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

An open frustum-shaped bucket has radii 28 cm and 21 cm and slant height 30 cm.
Find the area of metal sheet required to make it (curved surface + bottom circle only), in $cm^{2}$ (use π = $\frac{22}{7}$ ).