An open storage bin is a frustum whose top rim has radius 22 cm, whose closed base has radius 6 cm and whose depth is 30 cm. Find the area of sheet used to make it, in cm². (Take \π = 3.14 .)

Question

Accepted Answer

3102.32. l = √30^2 + 16^2 = √1156 = 34 cm. Curved surface = 3.14 × 34 × 28 = 2989.28 cm²; base = 3.14 × 6² = 113.04 cm². Total = 3102.32 cm². 2989.28 leaves out the base; 4622.08 also counts the open top; 2750.64 uses the depth 30 cm as the slant height.

An open storage bin is a frustum whose top rim has radius 22 cm, whose closed base has radius 6 cm and whose depth is 30 cm. Find the area of sheet used to make it, in $cm^{2}$ . (Take $π = 3.14.$ )

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

An open storage bin is a frustum whose top rim has radius 22 cm, whose closed base has radius 6 cm and whose depth is 30 cm. Find the area of sheet used to make it, in cm2. (Take π=3.14.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

An open storage bin is a frustum whose top rim has radius 22 cm, whose closed base has radius 6 cm and whose depth is 30 cm. Find the area of sheet used to make it, in $cm^{2}$ . (Take $π = 3.14.$ )