Ramesh's bucket is a frustum with end radii 260 mm and 100 mm and a depth of 120 mm. Find its capacity in litres, correct to two decimal places. (Take \π = 22/7 , 1 litre = 1000 cm³.)

Question

Accepted Answer

13.02 litres. First convert to centimetres: R = 26 cm, r = 10 cm, h = 12 cm. V = 1/3 × 22/7 × 12 × (676 + 100 + 260) = 22/7 × 4 × 1036 = 13024 cm³ = 13.02 litres. 13024 litres leaves the answer in cm³; 1.30 divides by 10000 instead of 1000; 9.76 drops the Rr term.

Ramesh's bucket is a frustum with end radii 260 mm and 100 mm and a depth of 120 mm. Find its capacity in litres, correct to two decimal places. (Take $π = \frac{22}{7}$ , 1 litre = $1000 cm^{3} .$ )

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More Class 10 Frustum of a Cone practice

Ramesh's bucket is a frustum with end radii 260 mm and 100 mm and a depth of 120 mm. Find its capacity in litres, correct to two decimal places. (Take π=722​, 1 litre = 1000cm3.)

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Frustum of a Cone practice

Ramesh's bucket is a frustum with end radii 260 mm and 100 mm and a depth of 120 mm. Find its capacity in litres, correct to two decimal places. (Take $π = \frac{22}{7}$ , 1 litre = $1000 cm^{3} .$ )