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Find the smallest number which, when divided by 8, 12 and 16, leaves a remainder of 3 in each case.

Class 10Fundamental Theorem of ArithmeticNumber Systems

A102
B46
C51
D56

Step-by-Step Solution

First find LCM(8, 12, 16).

8 = 2^{3}, 12 = 2^{2} \times 3, 16 = 2^{4}

. LCM =

2^{4} \times

3 = 48. Required number = 48 + 3 = 51.

Answer: C) 51

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