Three lines are graphed: x + y = 6, x - y = 2, and y = 1. The first two meet at (4, 2). Do all three lines pass through that single point (4, 2)?

Question

Accepted Answer

No, because y = 1 does not pass through (4, 2). The first two meet at (4, 2). But y = 1 requires y = 1, while the point has y = 2, so y = 1 does not pass through (4, 2). The three lines are not concurrent.

Three lines are graphed: $x + y = 6, x - y = 2$ , and $y = 1$ .
The first two meet at (4, 2). Do all three lines pass through that single point (4, 2)?

Step-by-Step Solution

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More Class 10 Graphical Method practice

Three lines are graphed: x+y=6,x−y=2, and y=1.The first two meet at (4, 2). Do all three lines pass through that single point (4, 2)?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Graphical Method practice

Three lines are graphed: $x + y = 6, x - y = 2$ , and $y = 1$ .
The first two meet at (4, 2). Do all three lines pass through that single point (4, 2)?