Practice30Create account

Find the largest number that divides 320 and 457, leaving remainders 5 and 7 respectively.

Class 10HCF and LCMNumber Systems
  • A45
  • B15
  • C137
  • D90

Step-by-Step Solution

Subtract the remainders first: 320 - 5 = 315 and 457 - 7 = 450. The required number is HCF(315, 450). and , so HCF = 5 = 45. Answering 137 uses the difference 457 - 320 without removing the remainders; 15 is a common factor but not the greatest; 90 divides 450 but not 315.
Answer: A) 45

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All HCF and LCM practice questions

More Class 10 HCF and LCM practice

Find the greatest number that divides 237, 388 and 618, leaving remainders 5, 11 and 9…Find the greatest number that divides 103, 199 and 343, leaving the SAME remainder in…Find the smallest number which, when divided by 9, 10 and 21, leaves a remainder of 4 in…A number leaves a remainder of 17 when divided by 22, and a remainder of 28 when divided…Find the least number which leaves a remainder of 8 when divided by 20, 24 or 45, and…