- A1683
- B1853
- C3366
- D1513
Step-by-Step Solution
LCM(5,6,7,8) = 840. Number = 840k + 3 must be divisible by 9. For k=1: 843 (8+4+3=15, no). k=2: 1683, digit sum 18 divisible by 9. So 1683.
Answer: A) 1683
Find the least number which when divided by 5, 6, 7 and 8 leaves a remainder 3 in each case, but when divided by 9 leaves no remainder.
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