Three runners on a circular track in Pune complete one round in 36, 48 and 60 seconds respectively. They start together from the same point. After how many seconds will all three be together at the starting point again?

Question

Accepted Answer

720. Required time = LCM(36, 48, 60). 36 = 2^2 x 3^2, 48 = 2^4 x 3, 60 = 2^2 x 3 x 5; LCM = 2^4 x 3^2 x 5 = 720 s.

Three runners on a circular track in Pune complete one round in 36, 48 and 60 seconds respectively. They start together from the same point.
After how many seconds will all three be together at the starting point again?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 HCF and LCM practice

Three runners on a circular track in Pune complete one round in 36, 48 and 60 seconds respectively. They start together from the same point.After how many seconds will all three be together at the starting point again?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 HCF and LCM practice

Three runners on a circular track in Pune complete one round in 36, 48 and 60 seconds respectively. They start together from the same point.
After how many seconds will all three be together at the starting point again?