A building in Indore is 30 m tall. Meena stands on level ground 30 √3 m from its foot, and then walks 20 √3 m straight toward the building. Find the angle of elevation of the top of the building from her new position.

Question

Accepted Answer

60°. New distance = 30 √3 - 20 √3 = 10 √3 m. tan(θ) = 3010 √3 = 3√3 = √3 => θ = 60°. At the start the angle was 30°, so walking closer has made the line of sight steeper.

A building in Indore is 30 m tall.
Meena stands on level ground 30 $3$ m from its foot, and then walks 20 $3$ m straight toward the building.
Find the angle of elevation of the top of the building from her new position.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

A building in Indore is 30 m tall.Meena stands on level ground 30 3​ m from its foot, and then walks 20 3​ m straight toward the building.Find the angle of elevation of the top of the building from her new position.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

A building in Indore is 30 m tall.
Meena stands on level ground 30 $3$ m from its foot, and then walks 20 $3$ m straight toward the building.
Find the angle of elevation of the top of the building from her new position.