A jogger in Bhubaneswar stands 60 m from the foot of a stadium floodlight tower, where the angle of elevation of the top is 45°. She jogs straight toward the tower and stops when the angle of elevation becomes 60°. Find the exact distance (in m) she has jogged.

Question

Accepted Answer

60 - 20 √3. From the first position, tan 45 = h/60 => h = 60 m. From the second position, tan 60 = 60/d => d = 60√3 = 20 √3 m (about 34.64 m). Distance jogged = 60 - 20 √3 m (about 25.36 m).

A jogger in Bhubaneswar stands 60 m from the foot of a stadium floodlight tower, where the angle of elevation of the top is 45°.
She jogs straight toward the tower and stops when the angle of elevation becomes 60°.
Find the exact distance (in m) she has jogged.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

A jogger in Bhubaneswar stands 60 m from the foot of a stadium floodlight tower, where the angle of elevation of the top is 45°.She jogs straight toward the tower and stops when the angle of elevation becomes 60°.Find the exact distance (in m) she has jogged.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

A jogger in Bhubaneswar stands 60 m from the foot of a stadium floodlight tower, where the angle of elevation of the top is 45°.
She jogs straight toward the tower and stops when the angle of elevation becomes 60°.
Find the exact distance (in m) she has jogged.