A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of 30°, which is approaching the foot of the tower with uniform speed. Six seconds later the angle of depression becomes 60°. Find the time (in seconds) taken by the car to reach the foot of the tower from the 60° position.

Question

Accepted Answer

3. Let height h. Far distance (30°) = h √3; near (60°) = h√3. Distance covered in 6 s = h √3 - h√3 = 2h√3. Remaining distance = h√3 = half of 2h√3. So time = 6/2 = 3 seconds.

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