At 8 a.m. in Chennai the angle of elevation of the Sun is 30°, and by noon it has become 60°. A boy 1.5 m tall stands on the same level ground at both times. By how many metres does his shadow shorten between 8 a.m. and noon? Give the exact value.

Question

Accepted Answer

√3. At 30° the shadow is 1.5/tan 30 = 1.5 √3 m (about 2.60 m). At 60° it is 1.5√3 = 0.5 √3 m (about 0.87 m). Shortening = 1.5 √3 - 0.5 √3 = √3 m (about 1.73 m).

At 8 a.m. in Chennai the angle of elevation of the Sun is 30°, and by noon it has become 60°.
A boy 1.5 m tall stands on the same level ground at both times.
By how many metres does his shadow shorten between 8 a.m. and noon? Give the exact value.

Step-by-Step Solution

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More Class 10 Heights and Distances practice

At 8 a.m. in Chennai the angle of elevation of the Sun is 30°, and by noon it has become 60°.A boy 1.5 m tall stands on the same level ground at both times.By how many metres does his shadow shorten between 8 a.m. and noon? Give the exact value.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

At 8 a.m. in Chennai the angle of elevation of the Sun is 30°, and by noon it has become 60°.
A boy 1.5 m tall stands on the same level ground at both times.
By how many metres does his shadow shorten between 8 a.m. and noon? Give the exact value.