Two friends, Asha and Bina, stand on opposite sides of a 30 m tall tower in line with its foot. The angle of elevation of the top is 30° from Asha and 60° from Bina. Find the distance (in m) between Asha and Bina.

Question

Accepted Answer

40 √3. Asha: tan 30 = 30/a => a = 30 √3. Bina: tan 60 = 30/b => b = 30√3 = 10 √3. Total = 30 √3 + 10 √3 = 40 √3 m.

Two friends, Asha and Bina, stand on opposite sides of a 30 m tall tower in line with its foot.
The angle of elevation of the top is 30° from Asha and 60° from Bina.
Find the distance (in m) between Asha and Bina.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

Two friends, Asha and Bina, stand on opposite sides of a 30 m tall tower in line with its foot.The angle of elevation of the top is 30° from Asha and 60° from Bina.Find the distance (in m) between Asha and Bina.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Heights and Distances practice

Two friends, Asha and Bina, stand on opposite sides of a 30 m tall tower in line with its foot.
The angle of elevation of the top is 30° from Asha and 60° from Bina.
Find the distance (in m) between Asha and Bina.