- A12
- B20
- C8
- D10
Step-by-Step Solution
The known frequencies total 30, so . Class marks 10, 30, 50, 70, 90, 110 give , and the mean 62.8 forces , so . Substituting gives , so and . "12" is 2, the other unknown; "20" is 2; "10" splits the 20 equally between the two classes without using the mean at all.
Answer: C) 8