- AThe mean rises by 0.5, because every boundary shifts by 0.5
- BThe class marks are unchanged, since (21 + 30)/2 = (20.5 + 30.5)/2 = 25.5, so the mean comes out the same either way
- CThe mean rises by 1 for every class in the table
- DThe mean simply cannot be found from inclusive classes
Step-by-Step Solution
The boundary correction lowers the lower limit by 0.5 AND raises the upper limit by 0.5, so the two shifts cancel in . The class marks 25.5, 35.5, 45.5, 55.5, 65.5 are identical both ways, so the mean is unaffected. (The correction does matter for the median and the mode, where the lower boundary is used on its own.) The other options assume the shift acts in only one direction.
Answer: B) The class marks are unchanged, since (21 + 30)/2 = (20.5 + 30.5)/2 = 25.5, so the mean comes out the same either way