Vikram tries to find two consecutive positive integers whose product is 30. If the smaller is x, then x^2 + x - 30 = 0. Using the discriminant, is a solution in positive integers possible, and what is D?

Question

Accepted Answer

D = 121, real distinct roots, possible (5 and 6). D = 1 - 4(1)(-30) = 1 + 120 = 121 > 0 and a perfect square, so roots are real, distinct, rational: x = -1 + 11/2 = 5, giving 5 and 6.

Vikram tries to find two consecutive positive integers whose product is 30.
If the smaller is $x$ , then $x^{2} + x - 30 = 0$ .
Using the discriminant, is a solution in positive integers possible, and what is D?

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More Class 10 Nature of Roots (Discriminant) practice

Vikram tries to find two consecutive positive integers whose product is 30.If the smaller is x, then x2+x−30=0.Using the discriminant, is a solution in positive integers possible, and what is D?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Nature of Roots (Discriminant) practice

Vikram tries to find two consecutive positive integers whose product is 30.
If the smaller is $x$ , then $x^{2} + x - 30 = 0$ .
Using the discriminant, is a solution in positive integers possible, and what is D?