- A57
- B56
- C58
- D55
Step-by-Step Solution
First multiple after 100 is 105, last before 500 is 497. AP: 105, ..., 497 with d = 7. 497 = 105 + (n-1)7 => 392 = 7(n-1) => n-1 = 56 => n = 57.
Answer: A) 57
How many multiples of 7 lie between 100 and 500?
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