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Which term of the AP 5, 17, 29, 41, ... is equal to 137?

Class 10nth Term of an APAlgebra — Sequences
  • A10th
  • B11th
  • C12th
  • D13th

Step-by-Step Solution

a = 5, d = 12. From 137 = 5 + (n - 1)12 we get 132 = 12(n - 1), so n - 1 = 11 and n = 12. Answering 11th stops at n - 1, the number of 12-steps taken rather than the term number (the same slip is made by anyone who treats 17 as the first term); 10th subtracts 1 twice over; 13th takes one step too many.
Answer: C) 12th

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