- A27
- B30
- C33
- D60
Step-by-Step Solution
AP = cm. Area of triangle OAP = OA AP = sq cm.
Answer: B) 30
From an external point P, tangents PA and PB are drawn to a circle with centre O. The length OP = 13 cm and radius OA = 5 cm.
The chord AB joins the two points of contact. Using the fact that OP is perpendicular bisector of AB, the area of triangle OAP is OA AP.
Find the area of triangle OAP in square cm.
Class 10Number of Tangents from a PointGeometry
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