- A60°
- B90°
- C120°
- D150°
Step-by-Step Solution
In quadrilateral OAPB, angle OAP = angle OBP = 90°. So angle AOB + angle APB = 180°, giving angle AOB = 180 - 60 = 120°.
Answer: C) 120°
Two tangents PA and PB are drawn from an external point P to a circle with centre O. If angle APB = 60°, then angle AOB equals:
Class 10Number of Tangents from a PointGeometry
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