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A bag contains 6 red and 4 blue balls. Two balls are drawn one after another WITHOUT replacement. What is the probability that both are red?

Class 10Probability Word ProblemsStatistics

A $\frac{1}{3}$
B $\frac{3}{5}$
C $\frac{9}{25}$
D $\frac{1}{2}$

Step-by-Step Solution

P(first red) =

\frac{6}{10}

, then P(second red) =

\frac{5}{9}

. Product =

\frac{6}{10} \times \frac{5}{9} = \frac{30}{90} = \frac{1}{3}

.

Answer: A)

\frac{1}{3}

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