From a pack of 52 playing cards, the 2, the 3, the 4 and the 5 of every suit are taken out and set aside. One card is drawn at random from the cards left behind. What is the probability that it is a numbered card from 6 to 10?

Question

Accepted Answer

5/9. Four ranks from each of the 4 suits are removed, i.e. 16 cards, leaving 36. The ranks 6, 7, 8, 9 and 10 are untouched, giving 5 x 4 = 20 cards. P = 20/36 = 5/9. 5/13 uses the old denominator 52; 4/9 counts the 16 cards that were removed; 5/18 counts the 6-to-10 cards of only two suits.

From a pack of 52 playing cards, the 2, the 3, the 4 and the 5 of every suit are taken out and set aside. One card is drawn at random from the cards left behind. What is the probability that it is a numbered card from 6 to 10?

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