Ishaan plays a board game using two dice of different colours, one yellow and one white. He throws both at the same time. What is the probability that the yellow die shows exactly twice as many dots as the white die?

Writing each throw as (white, yellow), the favourable throws are (1,2), (2,4) and (3,6); a white 4, 5 or 6 would need a yellow 8, 10 or 12, which no die has. So $P=\frac{3}{36}=\frac{1}{12}.\frac{1}{6}$ also counts (2,1), (4,2) and (6,3), but in those it is the WHITE die that is twice the yellow; $\frac{1}{18}$ misses one of the three throws; $\frac{1}{36}$ names only a single throw.