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An AP has 10 terms and $a_{1} + a_{10} = 40$ . What is $a_{3} + a_{8}$ ?

Class 10Properties and Selection of AP TermsAlgebra — Sequences

A20
B80
CIt cannot be found
D40

Step-by-Step Solution

Terms equally far from the two ends have the same sum:

a_{3} + a_{8} = (a + 2 d) + (a + 7 d) = 2 a + 9 d = a_{1} + a_{10} = 40

.

Answer: D) 40

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