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Find $k$ if $k^{2} + 4 k + 8, 2 k^{2} + 3 k + 6$ and $3 k^{2} + 4 k + 4$ are consecutive terms of an AP.

Class 10Properties and Selection of AP TermsAlgebra — Sequences

A−1
B0
C1
D2

Step-by-Step Solution

2(middle) = first + last:

4 k^{2} + 6 k + 12 = 4 k^{2} + 8 k + 12

, so

2 k = 0

and

k = 0

. The terms are 8, 6, 4.

Answer: B) 0

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