Practice30 Create account

For what value of k are 2k + 1, 13 and 5k − 3 three consecutive terms of an AP?

Class 10Properties and Selection of AP TermsAlgebra — Sequences

A4
B5
C2
D3

Step-by-Step Solution

2 \times 13 = (2 k + 1) + (5 k - 3)

, so

26 = 7 k - 2

and

k = 4

. Check: 9, 13, 17 have common difference 4.

Answer: A) 4

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Properties and Selection of AP Terms practice questions

More Class 10 Properties and Selection of AP Terms practice

Three numbers in AP add up to 24. What is the middle number?When three unknown numbers in AP are to be found, the most convenient way to write them…Four numbers in AP are written as a − 3d, a − d, a + d, a + 3d. What is their common…Five consecutive terms of an AP total 45. What is the third of them?In the AP 4, 9, 14, …, 99, what is the 3rd term from the end?