A guava tree was broken by a storm. The broken upper part bent over and its tip touched the ground at a point 12 m from the foot of the tree. The part still standing is 5 m tall. What was the original height of the tree, in metres?

Question

Accepted Answer

18. Standing part = 5 m. Broken part (hypotenuse) = √5^2 + 12^2 = √25 + 144 = √169 = 13 m. Original height = 5 + 13 = 18 m.

A guava tree was broken by a storm.
The broken upper part bent over and its tip touched the ground at a point 12 m from the foot of the tree.
The part still standing is 5 m tall.
What was the original height of the tree, in metres?

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More Class 10 Pythagoras Theorem practice

A guava tree was broken by a storm.The broken upper part bent over and its tip touched the ground at a point 12 m from the foot of the tree.The part still standing is 5 m tall.What was the original height of the tree, in metres?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Pythagoras Theorem practice

A guava tree was broken by a storm.
The broken upper part bent over and its tip touched the ground at a point 12 m from the foot of the tree.
The part still standing is 5 m tall.
What was the original height of the tree, in metres?