The large tap fills the drum 10 minutes faster than the small tap. With both taps open, the drum fills in 6 minutes 40 seconds. How long does the small tap take alone?

Question

Accepted Answer

20 minutes. 6 min 40 s = 203 min. 1x + 1x + 10 = 320 20(2x + 10) = 3x(x + 10) 3x^2 - 10x - 200 = 0 (x - 10)(3x + 20) = 0 . Reject x = - 203 ; large tap 10 min, small tap 20 min.

The large tap fills the drum 10 minutes faster than the small tap. With both taps open, the drum fills in 6 minutes 40 seconds. How long does the small tap take alone?

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