An express train takes 1 hour less than a passenger train to travel 132 km. The express runs 11 km/h faster than the passenger. The speed of the passenger train (km/h) is: Solve the equation.

Question

Accepted Answer

33. 132/x - 132/x+11 = 1, 132(11)/x(x+11)=1, x^2+11x-1452=0, (x+44)(x-33)=0. x = 33 km/h.

An express train takes 1 hour less than a passenger train to travel 132 km. The express runs 11 km/h faster than the passenger. The speed of the passenger train (km/h) is:
Solve the equation.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Quadratic Word Problems practice

An express train takes 1 hour less than a passenger train to travel 132 km. The express runs 11 km/h faster than the passenger. The speed of the passenger train (km/h) is:Solve the equation.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Quadratic Word Problems practice

An express train takes 1 hour less than a passenger train to travel 132 km. The express runs 11 km/h faster than the passenger. The speed of the passenger train (km/h) is:
Solve the equation.