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The sum of the ages (in years) of a father and his son is 45. Five years ago, the product of their ages was 124. The son's present age (in years) is:

Class 10Quadratic Word ProblemsAlgebra — Quadratics

A8
B10
C18
D9

Step-by-Step Solution

Son

x

, father

45 - x . (x - 5) (40 - x) = 124, 45 x - x^{2} - 200 = 124, x^{2} - 45 x + 324 = 0, (x - 9) (x - 36) = 0

. Son = 9 (36 rejected, exceeds total sensibly).

Answer: D) 9

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