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Two positive integers leave the SAME remainder when each is divided by d. Then d must always divide:

Class 10Real NumbersNumber Systems
  • Atheir difference
  • Btheir sum
  • Ctheir product
  • Deach of the two numbers

Step-by-Step Solution

Write a = dq₁ + r and b = dq₂ + r with the same r. Subtracting, a − b = d(q₁ − q₂), so d divides a − b. It need not divide a or b themselves (17 and 32 both leave remainder 2 on division by 5, yet 5 divides neither), nor their sum or product in general. This is exactly the trick used in every “greatest number leaving remainder r” problem.
Answer: A) their difference

Key idea: Euclid's Division Lemma and HCF

**Lemma**: For positive integers a, (with ), there exist UNIQUE with and 0 ≤ .

This is just formal long division — is the quotient, is the remainder.

**Algorithm to find HCF(a, b)** with :
1. Apply lemma: .
2. If , HCF = .
3. If ≠ 0, replace (a, b) with , r) and repeat.

**Example**: HCF(420, 130)
→ HCF = 10.

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