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Two ribbons of length 108 cm and 144 cm are to be cut into pieces of equal length, with nothing left over and each piece as long as possible. How many pieces are obtained altogether?

Class 10Real NumbersNumber Systems
  • A6
  • B7
  • C12
  • D36

Step-by-Step Solution

Longest piece = HCF(108, 144). and , so HCF = cm. Pieces = 108/36 + 144/36 = 3 + 4 = 7. Answering 36 gives the LENGTH of a piece, not the number of pieces.
Answer: B) 7

Key idea: Euclid's Division Lemma and HCF

**Lemma**: For positive integers a, (with ), there exist UNIQUE with and 0 ≤ .

This is just formal long division — is the quotient, is the remainder.

**Algorithm to find HCF(a, b)** with :
1. Apply lemma: .
2. If , HCF = .
3. If ≠ 0, replace (a, b) with , r) and repeat.

**Example**: HCF(420, 130)
→ HCF = 10.

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