A field is in the shape of a rectangle whose diagonal is 17 m. The length exceeds the breadth by 7 m. Let breadth = x. Using the diagonal (Pythagoras) and factorisation, find the length (in m).

Question

Accepted Answer

15. x^2 + (x+7)^2 = 17^2 = 289, so 2x^2 + 14x + 49 = 289, i.e. 2x^2 + 14x - 240 = 0, x^2 + 7x - 120 = 0 = (x + 15)(x - 8). Breadth x = 8, so length = 8 + 7 = 15 m.

A field is in the shape of a rectangle whose diagonal is 17 m. The length exceeds the breadth by 7 m.
Let breadth = $x$ . Using the diagonal (Pythagoras) and factorisation, find the length (in m).

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More Class 10 Roots by Factorisation practice

A field is in the shape of a rectangle whose diagonal is 17 m. The length exceeds the breadth by 7 m.Let breadth = x. Using the diagonal (Pythagoras) and factorisation, find the length (in m).

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Roots by Factorisation practice

A field is in the shape of a rectangle whose diagonal is 17 m. The length exceeds the breadth by 7 m.
Let breadth = $x$ . Using the diagonal (Pythagoras) and factorisation, find the length (in m).