A train travels 360 km at a uniform speed of x km/h. If the speed had been 5 km/h more, the journey would take 1 hour less. Which quadratic (to be solved by factorisation) models the speed?

Question

Accepted Answer

x^2 + 5x - 1800 = 0. 360/x - 360/x+5 = 1. Multiply: 360(x+5) - 360x = x(x+5), so 1800 = x^2 + 5x, giving x^2 + 5x - 1800 = 0.

A train travels 360 km at a uniform speed of $x$ km/h. If the speed had been 5 km/h more, the journey would take 1 hour less.
Which quadratic (to be solved by factorisation) models the speed?

Step-by-Step Solution

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More Class 10 Roots by Factorisation practice

A train travels 360 km at a uniform speed of x km/h. If the speed had been 5 km/h more, the journey would take 1 hour less.Which quadratic (to be solved by factorisation) models the speed?

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Roots by Factorisation practice

A train travels 360 km at a uniform speed of $x$ km/h. If the speed had been 5 km/h more, the journey would take 1 hour less.
Which quadratic (to be solved by factorisation) models the speed?