- AC(13, 10) and M(3, 0)
- BC(15, 12) and M(5, 2)
- CC(15, 12) and M(7, 4)
- DC(15, 12) and M(3, 0)
Step-by-Step Solution
For gives and ; gives and , so = (15, 12). For on AB with ratio 1 : 3: and , so (13, 10) mis-solves as ; (5, 2) treats as the midpoint of AB; (7, 4) uses the ratio 3 : 1 instead of 1 : 3.
Answer: D) C(15, 12) and M(3, 0)