Find the two points of trisection of the segment joining A(3, -4) and B(-6, 8).

Ratio 1 : 2 gives $x=\frac{-6+6}{3}=0$ and $y=\frac{8-8}{3}=0$, i.e. (0, 0). Ratio 2 : 1 gives $x=\frac{-12+3}{3}=-3$ and $y=\frac{16-4}{3}=4$, i.e. (-3, 4). The pair (1, 0) and (-2, 4) divides the coordinate differences by 3 but adds them back to the wrong endpoint; (-1.5, 2) is the midpoint used in place of a trisection point; the last option quotes B itself as one of the two points.