If A(-2, 3), B(6, 7) and P divides AB so that AP = 1/4 AB, find the coordinates of P.

(0, 4). AP=1/4AB => AP:PB=1:3. x=1 · 6+3 · (-2)/4=6-6/4=0; y=1 · 7+3 · 3/4=7+9/4=4. So (0, 4).

If A(-2, 3), B(6, 7) and P divides AB so that AP = $\frac{1}{4}$ AB,
find the coordinates of P.

Class 10Section FormulaGeometry — Coordinates

AP=

\frac{1}{4}

AB => AP:PB=1:3.

x = \frac{1 \cdot 6 + 3 \cdot ( - 2 )}{4} = \frac{6 - 6}{4} = 0

;

y = \frac{1 \cdot 7 + 3 \cdot 3}{4} = \frac{7 + 9}{4} = 4

. So (0, 4).

Answer: A) (0, 4)

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