Practice30Create account

The segment joining A(-2, -3) and B(6, 5) meets the -axis at a point C.
Find the coordinates of C.

Class 10Section FormulaGeometry — Coordinates
  • A(3, 0)
  • B(2, 0)
  • C(0, 1)
  • D(1, 0)

Step-by-Step Solution

On the -axis , so , giving and : 5. Then , so = (1, 0). (3, 0) uses the inverted ratio 5 : 3; (2, 0) takes the midpoint's -coordinate instead of solving for the crossing; (0, 1) writes the correct number in the wrong slot — a point on the -axis has the form , 0), not (0, ).
Answer: D) (1, 0)

Master this chapter in 30 minutes a day.

Don't just memorise the answer — build a daily practice habit.

Practice 5 Similar Questions Free →

All Section Formula practice questions

More Class 10 Section Formula practice

A triangle has vertices A(-2, 4), B(6, 0) and C(2, 8). E is the midpoint of AB. The…A straight walking trail runs from a gate G(-4, -1) to a viewpoint V(11, 14). Two rest…A point P divides the segment joining A(2a, 0) and B(0, 3b) in the ratio 1 : 2. The…A straight canal runs from lock A(-3, -2) to lock B(9, 10). Two sluice gates P and Q…The point P(x, -1) lies on the segment joining A(2, 5) and B(8, -4). Find the ratio AP :…