Suppose both roots of x^2 - bx + 36 = 0 are equal positive integers. Thinking about the product of roots being 36, what is the value of each root?

Question

Accepted Answer

6. If both roots are equal to r, product r x r = 36, so r^2 = 36 and r = 6 (positive). The equation is x^2 - 12x + 36 = 0.

Suppose both roots of $x^{2} - b x + 36 = 0$ are equal positive integers.
Thinking about the product of roots being 36, what is the value of each root?