The product of two consecutive positive integers is 56.
If the smaller integer is $x$ , write the situation as a quadratic equation in standard form and state its positive root $x$ .

Question

The product of two consecutive positive integers is 56. If the smaller integer is x, write the situation as a quadratic equation in standard form and state its positive root x.

Accepted Answer

7. x(x + 1) = 56 gives x^2 + x - 56 = 0, i.e. (x - 7)(x + 8) = 0. The positive root is x = 7 (integers 7 and 8).

The product of two consecutive positive integers is 56.
If the smaller integer is $x$ , write the situation as a quadratic equation in standard form and state its positive root $x$ .

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

The product of two consecutive positive integers is 56.If the smaller integer is x, write the situation as a quadratic equation in standard form and state its positive root x.

Step-by-Step Solution

Master this chapter in 30 minutes a day.

More Class 10 Standard Form and Roots practice

The product of two consecutive positive integers is 56.
If the smaller integer is $x$ , write the situation as a quadratic equation in standard form and state its positive root $x$ .