- A10.5–15.5
- B11–15
- C15.5–20.5
- D10.5–14.5
Step-by-Step Solution
The highest frequency is 15, so the modal class is 11–15. The gap between 5 and 6 is 1, so subtract and add 0.5: in continuous form it is 10.5–15.5. The mode formula must use these boundaries, otherwise l is wrong by 0.5.
Answer: A) 10.5–15.5